A free particle of energy E and de Broglie wavelength λ enters into a region of
constant potential V = 0.75 E. What is the de Broglie wavelength of the particle is this
region?
(A) 2λ
(B) 3λ
(C) λ/2
(D) λ/3
Answers
Answered by
0
Answer:
Theinitialkineticenergyoffreeparticle:
E=
2m
p
2
→=
2mE
Debrogliewavelength:
λ=
p
h
=
2mE
h
Energyoftheparticlewhenitenterstheregion:
E
f
=E−U
So,itswavelengthbecomes:
λ
f
=
2mE
f
h
=
2m(E−U)
h
λ
f
2
=
2mE
h
2
(
E−V
E
)=
2mE
h
2
(
1−U/E
1
)
λ
f
=
2mE
h
(
1−U/E
1
)
1/2
=λ(1−U/E)
−1/2
Similar questions