Physics, asked by abhinavkr5985, 11 months ago

A free U238 nucleus kept in a train emits an alpha particle. When the train is stationary, a nucleus decays and a passenger measures that the separation between the alpha particle and the recoiling nucleus becomes x at time t after the decay. If the decay takes place while the train is moving at a uniform velocity v, the distance between the alpha particle and the recoiling nucleus at a time t after the decay, as measured by the passenger, is
(a) x + v t
(b) x − v t
(c) x
(d) depends on the direction of the train

Answers

Answered by HrDesi0001
3

Answer:

(D) depends on the direction of the train

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