Question

a freely falling body covers 11/36th
of distance in the last second find the height from which it falls ​

Answer 1

Explanation:

The body falls through

h−(7h/16)=9h/16 during (n−1) seconds and fall through 'h' in n seconds

using s=ut+1/2at^2

9h/16=5(n−1)^2

and h=5n2

dividing 9/16=(n−1)^2/n^2

we get n=4

Therefore h=5×42=80m