Question

A freely falling body covers 44.1 m in the last second of its journey. Find the total distance travelled by the

body​

Answer 1

Answer:

d= 125 m.

Explanation:

d=ut + 1/2 at^2

Now at t = t-1

d'=u(t-1)+1/2a(t-1)^2

Here u =0 and a = g= 10 m/s^2(approx)

d=5t^2

d'=5(t-1)^2

d-d'=44.1 m = 5[2t-1]

8.82 = 2t-1

4.96 = t (Approx 5 sec)

Now,

d= 5*(5)^2

d= 125 m.

If more accurate answer is required then take g=9.81 m/s^2.