A freely falling body covers half of its journey from the top of the tower in 0.5 sec .Find the force gravitation acting between them
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we assume the height of tower to be x. so according to law of motion
distance travelled (s) = ut +1/2at^2
here s= 1/2x
also initial velocity is zero,so u is also zero
so,. 1/2x= 1/2 a t^2
on solving for a and putting t = 0.5 we get
a= 4x
.....
distance travelled (s) = ut +1/2at^2
here s= 1/2x
also initial velocity is zero,so u is also zero
so,. 1/2x= 1/2 a t^2
on solving for a and putting t = 0.5 we get
a= 4x
.....
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