Question

A freely falling body covers _______ of total distance in 3rd second

Answer 1

Given that,

Time = 3 sec

We need to calculate the distance

Using equation of motion

$s=ut+\dfrac{1}{2}gt^2$

Where, u = initial velocity

g = acceleration due to gravity

t = time

s = distance

$s=0+\dfrac{1}{2}\times9.8\times3^2$

$s=44.1\ m$

Hence, A freely falling body covers 44.1 m distance.