Question

A freely falling body describes a distance of x in the first 2 seconds and a distance of y in next 2 seconds, then relation between x and y is

Answer 1

Answer :

◈ Distance covered by freely falling object in first 2 seconds is x and in next 2 seconds is y$.$

We have to find rekation between x and y$.$

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✻ Distance covered in first 2s :

➝ d = ut + (1/2)gt²

➝ d = (0×2) + (1/2)(10×2²)

➝ d = 40/2

➝ d = 20m

✻ Distance covered in first 4s :

➝ D = ut + (1/2)gt²

➝ D = (0×4) + (1/2)(10×4²)

➝ D = 160/2

➝ D = 80m

Hence, distance covered in next 2 seconds will be

➝ d' = D - d

➝ d' = 80 - 20

➝ d' = 60m

◈ Relation between d and d' :

⇒ d'/d = 60/20

⇒ d'/d = 3

⇒ d' = 3d