Question

A freely falling body reaches the ground after 4s what is the height which it reaches​

Answer 1

$\huge\boxed{\mathtt\red{SOLUTION:-}}$

Given :-

1. Time in which the body reaches ground (t) = 4 s
2. Acceleration due to gravity (g) = 10 m/s²

To Find :-

1. height from which it falls (s).

Solving :-

applying the following formula :-

$\large\boxed{\mathtt\blue{s=\frac{1}{2}gt²:-}}$

where,

◑ s = height

◑ g = acceleration due to gravity

◑ t = time

now, putting the values :-

✒ $\large{\mathtt{s =\frac{1}{2}×10\:m/s²×16 s²}}$

∴ s = 80 m

Answer :-

$\small\boxed{\mathtt\green{The\:height\:which\:it\:reaches\:is\:80\:m}}$