Question

a freely falling body takes t seconds to travel first one by X distance then time of decent is​

Answer 1

Answer:

Time of Decent =  t√X

Explanation:

S = ut + (1/2)at²

Let say total Height = H

Then 1/X distance = H/X

S = H/X

u = 0  

t = t

a = g

H/X  = (1/2)gt²

=> H = Xgt²/2

time of decent is​= Td

H = (1/2)g(Td)²

=> (Td)² = 2H/g

=>  (Td)² = 2(Xgt²/2)/g

=> (Td)² = Xt²

=> Td = t√X

Time of Decent =  t√X