Question

a freely falling body traveled xm in nth sec then distance traveled in n-1th second is ??.......

Answer 1

Answer:

Sn = u + ( n-1/2 ) a

u = 0

x = a ( 2n-1 / 2 )

a = 10

x = 5 ( 2n-1 )

= 10n - 5

when n= n-1 ,

Sn = 5 × 2(n-1 ) -1

= 5 × 2n - 2 - 1

= 5 ( 2n-3 )

Sn : x can be given as ,

5 ( 2n-3 ) : 5 ( 2n-1 )

5 and 2n gets cancelled

-3 : -1

minus gets cancelled

3 : 1

at n-1th sec , the body travels x/3 m