Question

A freely falling body travels. Of total distance in 5th second

Answer 1

Answer:

36%

Explanation:

first calculate 5th second

S5=ut+1/2 gt^2

1/2×10×5^2

=125

now,

calculate 4th second

S4=1/2×10×4^2

80

so,s=s5-s4/S5

125-80/125×100=36%