Question

A freely falling body travels _ of total distance in 5th second (which is last second)

Answer 1

Explanation:

For a freely falling body,

Initial velocity, u = 0 m/s

Acceleration due to gravity =9.8m/s

Time, n = 5

Distance travelled in 5th second =

S = u + 1/2a(2n - 1)

S = 0 + 1/2 × 9.8 × (2×5 - 1)

S = 4.9 × 9

S = 44.1 m

Hence, Distance covered in 5th second = 44.1m

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