Question

A freely falling body travels ____ of total distance in 5th second

Answer 1

Hi friend,

Solution:-
u = 0.t = 5s

s = u t + 1/2 gt^2

= 0*5 + 1/2 *9.8 * 5^2

= 122.5 m..i hope it helps you


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Answer 2

Answer:

36%

Explanation:

because,

case(1):distance travelled in nth second

sn=u+a(n-1/2)

sn=0+g(5-1/2)

=g(9/2)

=9.8×4.5=44.1m

case(2):distance travelled in 5 seconds

s=ut+1/2at^2

s=0t+1/2at^2

s=1/2g(5)^2

s=9.8/2×25

s=4.9×25=122.5m

distance could travelled in 5s is 122.5m but it travelled only 44.1 m.

so, IF 122.5 ---100%

then 44.1 --- x%

so 44.1×100/122.5

=4410÷122.5

=36%