Question

A freely falling particle acquires a velocity Vms-1 after falling for n sec starting from rest at t = 0 . The height through which it falls from time t = (n – 2) s and t = n s in meter is​

Answer 1

Explanation:

v

2

=2gs

v=

2gs

s=80,V=v

V=

2×10×80

=

1600

=40m/s

2V=

2gS

′

24×1600=2×10×S

′

S

′

=320m

Further distance =320−40=280m