Question

A freely falling particle acquires a velocity Vms-1 after falling for n sec starting from rest at
t = 0 . The height through which it falls from time t = (n – 2) s and t = n s in meter is

Answer 1

If

t¹ =0

t²=(n – 2) s

t³=ns

Then

t¹+t²=t³

so

0+(n – 2) s=ns

0+(n – 2) = ns/s

0+n-2 = n

n = 0+n-2

n-n = 2

So this must be your answer dear friend.

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