Question

a freely falling particle, falling from a tower of height h covers a distance of h/2 in the last second of its motion. the height of the tower is g=10m/s2

Answer 1

We have the formula - S = U + a/2(2N-1) [ WHERE U = INITIAL SPEED , & N = value of TIME IN Tth SECOND]

so using the formula

h/2 = u + a/2(2t-1)

h/10 = 2t-1 { u=0 & a=10}

t = h+10/20

so, total time = h+10/20

now by formula = h=ut + 1/2at^2, (u=0 a=10)

h=h^2+100+20h/80

on solving - h = 58.28 metres.

Answer 2

Explanation:

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