Question

a freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour. What is the freight trains original speed?

Answer 1

Answer:

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150(x+5)-150x=x(x+5)

150(x+5)-150x=x(x+5)150x+750-150x=x^2+5x

150(x+5)-150x=x(x+5)150x+750-150x=x^2+5xx^2+5x-750=0

150(x+5)-150x=x(x+5)150x+750-150x=x^2+5xx^2+5x-750=0(x-25)(x+30)=0

150(x+5)-150x=x(x+5)150x+750-150x=x^2+5xx^2+5x-750=0(x-25)(x+30)=0x=25