Question

a frequency of sound in air 500hzand velocity is 320m/s. find wavelength and time periods in sound wave​

Answer 1

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❒ Required Answer:

☁️ GiveN:

• Frequency = 500 Hz
• Velocity of sound = 320 m/s (ATQ)

☁️ To FinD:

• Wavelength of sound wave....?
• Time period of sound wave...$?$

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❒ How to solve?

Wavelength of the sound wave refers to the distance between the crests and troughs or the length of a complete Crest and troughs.

Frequency is the number of complete cycles or vibrations per unit time. Time period is the time taken by a wave to complete one full cycle.

So, we can say that,

• Frequency = 1/Timeperiod

We know,

• Speed = Distance / Time

And here, the distance is the wavelength and time is the time period of the wave. So,

• Velocity of sound = Wavelength /Time period
• We know, 1/Timeperiod = Frequency

So, Velocity can be written as,

• Velocity = Wavelength × Frequency

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❒ Solution:

We have,

• Frequency = 500 Hz
• Velocity of sound = 320 m/s

According to formula,

➝ 320 = 500 × Wavelength

➝ Wavelength = 320/500 m

➝ Wavelength = 0.64 m

✒ Therefore, Wavelength of the wave = 0.64 m

Also, we are given,

• Frequency = 500 Hz

According to Time period relation,

➝ 500 = 1/Time period

➝ Time period = 1/500 s

➝ Time period = 0.002 s

✒ Therefore, Time period of the cycle = 0.002 s

✳ Hence, solved!

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