Question

A frictionless wire AB is fixed on a sphere of radius R. A very small spherical ball slips on this wire. The

time An object is projected upwards with a velocity of 100

m / s

. It will strike the ground after

(approximately):​

Answer 1

Answer:

Time taken by this ball to slip from A to B is:

AB = R/(cos theta)          theta = 45 degree                          

AB = √2 R = 2R/√2 = 2R cosѲ

Explanation:

Now using velocity-time equation and put values in them  

v-u=at

v=u+1/2at2

=-100+1/2* gcosѲ *t2…………………….(1)

[where 2R cosѲ = 1/2x gcosѲ x t2 , t = 2 √R/g]

Put them into eq (1) and get the result.

Answer 2

Answer:

Explanation:

Cos@