A frog at the bottom of a well 10 metres deep, begins to climb out. He climbs up 3 metres every day but slips back 2 metres each night. After how many days will he be free?
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Answer:
Every 24hr(one day) the frog travels 3m up and slides back 2m => it retains 1m every 24h (a day) on the 8th day it is at a height of 8m from the botom, 2m to go to come out of the well, the 9th day since it has the capability to climbe 3m befor the night takes place, the frog is out of the well in day light. Atlist 1m away from the well.
Since it slids back because of gravity
I concider up as negative(against gravitational pul) and down as positive
(10m -3m + 2m)/(1m/day)=9m/(1m/day) = 9days
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Answer:
The Frog would take 7 days to get out of the well.
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