Math, asked by Avayviolet1921, 9 months ago

A frog falls into a well that is 18 ft deep. Every day the frog jumps up a total distance of 6 ft. At night , as the frog grips the slimy well walls, it slips back down by 2 ft. At this rate, how many days will it take the frog to jump to the rim of the well?

Answers

Answered by shreshth0000
0

Answer:

nearly 4 days and 8 to 10 hours

Answered by bharatiravi1016
0

Answer:

4 days

Step-by-step explanation:

As first day the frog jumps 6 feet

nd it will slip back 2 feet that means

6-2 it would have jumped 4 feet

second day same 4+6 = 10-2 = 8

third day same 8+6 = 14-2 = 12

fourth day 12+6= 18

Thus it reaches the rum by fourth day

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