A frog has fallen into a pit that is 30m deep.
Each day the frog climbs 3m, but falls back 2m at night.
How many days does it take for him to escape?
Answers
Answer:30days
Step-by-step explanation:The frog climbs 3m in day and falls 2m at night.
Therefore ,the frog can climb 1 m per day.
Hence, in 30 days he can climb 30m.
Therefore, answer is 30 days.
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Answer:
28 days
Step-by-step explanation:
It is given that the distance climbed by the frog during daytime=3m
The distance by which the frog falls during night=2m
Therefore,
the effective distance covered by the frog in a day
=the distance climbed by the frog during daytime - The distance by which the frog falls during the night.
=3m-2m=1m
Thus, effectively the frog takes one day to climb one meter. Therefore, it should take 27×1 days to climb up 27m……………………(1.1)
However, on the 28th day, once the frog climbs up 3m in the daytime, it will get out of the well……….(1.2)
Therefore, from (1.1) and (1.2), we see that the number of days required for the frog to get out of the well = Time taken to climb 27m+ 1day to ascend 3m during daytime
=27days+1 day=28days
Thus, the required answer is 28 days.
Note: We should not consider that the effective length travelled by the frog on all days is 1m because it just needs to reach the top of the well, which it does on the daytime of the 28th day. Therefore, after the 28th day’s daytime, we should not consider that it would fall 2m again at night as it would have already gone out.