Question

A frog is capable of jumping to a height of 2.62 m. what should be the take off velocity of the frog?
Take the acceleration due to gravity as 9.8 m/s^2

pls solve it....​

Answer 1

$\boxed{\green{\mathsf{Answer}}}$

$\mathsf{u ≈ 7m{s}^{-1} }$

$\boxed{\green{\mathsf{Explanation}}}$

Given:

• S = 2.62m
• a = -9.8m/s²
• v = 0

To Find:

initial velocity

Solution:

$\boxed{\red{\bold{{v}^{2} - {u}^{2} = 2as}}}$

$\mathsf{{0}^{2} - {u }^{2} = 2(-9.8)(2.62)}$

$\mathsf{- {u }^{2} = -51.352}$

$\mathsf{ {u }^{2} = 51.352}$

$\mathsf{u = \sqrt{51.352}}$

$\mathsf{u ≈ 7m{s}^{-1} }$

$\texttt{\blue{Aravind}\: \red{Reddy}....!}$