Question

A frog is stuck at the bottom of the well.Each time it leaps to come out.It cover halfs the distance left and climbs another half a meter .If it is out in 4 leaps .Tbe height of the well metere

Answer 1

Answer:  Let D be the depth of the well and Ln the distance left after nth jump

L1 = D - (D/2 - 1/2) = (D - 1) / 2   distance left after 1st jump

L2 = (L1 - 1) /2 =  [(D -1) / 2 -1] /2 = (D - 3) /4

L3 = (D - 7) / 8    and L4 = (D - 15) / 16     using the same progressions

But L4 = 0 since that jump gets him out

Then D = 15

1)   L1 = 7.5 - .5 = 7

2) L2 = 3.5 - .5 = 3

3) L3 = 1.5 - .5 = 1

4) L4 = .5 - .5 = 0