(a) From the 30 tickets marked with the first 30 natural number. One is drawn at random. Find the chance that the number on it is a multiple of (0) 3 or 7 and (ii) 3 or 5
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Step-by-step explanation:
P(multiple of 3 or 7)=12/30=0.4
P(multiple of 3 or 5)= 14/30=0.46
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