a) From the roof of a house of 10m high, the angle of elevation of the top of a temple
of 60m high is observed to be 60°. Find the distance between the house an
temple
house and the temple
Answers
Step-by-step explanation:
The given scenario is shown in the attached figure.
Given:
DE=10
∠CDB=45
o
∠CDA=60
o
To find: AB
Solution:
tan∠CDB=
CD
CB
⇒tan45
o
=
CD
DE
∵CB=DE
1=
CD
10
CD=10 m
tan∠CDA=
CD
CA
⇒tan60
o
=
10
CA
3
=
10
CA
CA=10
3
m
AB=AC+BC
AB=10+10
3
≈27.32 m
Hence, the height of the tower is 27.32 m
solution
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SIMILAR QUESTIONS
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From the top of a 7 m high building the angle of elevation of the top of a tower is 60
o
and the angle of depression of its foot is 45
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.Find the height of the tower.
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From the top of a 7 m high building, the angle of elevation of the top of a cable tower measures 60
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