Question

(a) From the sum of 3x - y + 11 and - y-11, subtract 3x - y - 11.
(b) From the sum of 4 + 3x and 5 - 4x + 2x2 subtract the sum of​

Answer 1

Answer:

From the sum of 3x - y + 11 and - y - 11, subtract 3x - y -11

First, we add 3x - y + 11 and - y - 11

= 3x - y + 11 + (- y - 11)

= 3x - y + 11 - y - 11

= 3x - 2y

Now from 3x - 2y subtract 3x - y - 11

= 3x - 2y - (3x - y - 11)

= 3x - 2y - 3x + y + 11

= - y + 11

(b) From the sum of 4 + 3x and 5 – 4x + 2x2 , subtract the sum of 3x2 – 5x and - x2 + 2x + 5

Add 4 + 3x and 5 - 4x + 2x2

= 4 + 3x + 5 - 4x + 2x2

= 2x2 - x + 9

Now add 3x2 - 5x and - x2 + 2x + 5

= 3x2 - 5x + ( - x2 + 2x + 5)

= 3x2 - 5x - x2 + 2x + 5

= 2x2 - 3x + 5

Now subtract 2x2 - 3x + 5 from 2x2 - x + 9

= 2x2 - x + 9 - (2x2 - 3x + 5)

= 2x2 - x + 9 - 2x2 + 3x - 5

= 2x + 4