Question

a fruit basket contains 3 mangoes 4 oranges and 3 apples. Another fruit basket contains 5 mangoes, 5 oranges and 5 apples. One basket is selected at random. 1. what is the probabilities that both are mangoes?
2. one is apple and one is orange? 3. first fruit basket is selected given both the fruit drawn are mangoes?​

Answer 1

Answer:

3/10. 5/10 is right answer because sum of all fruits divided by mangoes

Answer 2

Answer:

= 76/144.

Given:

number of mangoes = 3

number of oranges = 4

number of apples in second basket = 3

number of mangoes in second basket = 5

number of oranges in second basket = 5

Solution:

The probability that both are apples = (5/12) . (4/12) = 20/144

The probability that both are oranges = (7/12) . (8/12) = 56/144

Hence, the probability that the fruits are both apples or both oranges = (20/144) + (56/144)

= (20+56)/144

= 76/144.

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