Math, asked by AdvikaRai7127, 8 months ago

A fruit merchant earns a profit of rs. 6 per bag oranges sold and a loss of rs. 4 per bag of grapes sold. a, Merchant sells 1800 bags of oranges and 2500 bags of grapes. What is the total profit or loss. b, What is the number of bags of oranges to be sold to have neither profit nor loss if number of grapes bags sold is 900

Answers

Answered by Anonymous
78

Given,

Profit for one bag of orange = rs. 6

Loss for one bag of grapes = rs. 4

Sold bags of oranges = 1800

Sold bags of grapes = 2500

a) For, calculating the total profit or loss, we have first calculate the total profits from oranges and total loss from grapes.

Total profit from oranges = 1800×6 = rs. 10800

Total loss from grapes = 2500×4 = rs. 10000

Now,the amount of profit is greater than the amount of loss,the deal is a profitable deal.

So,the total profit = 10800-10000 = rs. 800

Hence,the total profit amount is rupees 800.

b) For calculating the number of bags of oranges to be sold to neutralize the profit or loss against the sales of 900 bags grapes,we need to calculate the loss by selling 900 bags of grapes.

Total loss from 900 bags of grapes = 900×4 = 3600

So,to neutralize the loss,we have to earn a profit of rs. 3600 from the sales of oranges.

So,

Rs. 6 profit = 1 bag

Rs. 1 profit = 1/6 bag

Rs. 3600 profit = 3600/6 = 600 bags

Hence,we need to sell 600 bags of oranges.

Answered by usha80387
4

Step-by-step explanation:

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