Math, asked by midnight13, 11 months ago

A fruit seller bought 2 dozen oranges at ₹45 per dozen . Thirteen oranges were found rotten . At what rate should he sell each orange to gain 10%​

Answers

Answered by Koleplayer
85

Answer:

Step-by-step explanation:

Cost per dozen = Rs 45

Total C.P= Rs (45 x 2) = Rs 90

If gain = 10% on the whole deal

Then, S.P of 2 dozen of oranges = (1+\frac{10}{100} ) x 90

                                                       = \frac{110}{100} x 90

                                                         = Rs 99

Total Oranges= 2 dozen= (2 x 12) oranges = 24 oranges

C.P of each Orange = Rs \frac{45}{24}

Oranges found rotten = 13

Remaining oranges = (24-13) oranges = 11 oranges

S.P of each of the remaining orange to gain 10% = Rs \frac{99}{11}

                                                                                 = Rs 9

Ans) The fruit seller should sell each orange at Rs 9 to gain 10% on the                   whole deal

Answered by vastav2530
36

Answer:

CP of 24 oranges = 45×2

=90

SP of 24 oranges =[CP×(100+gain%)]÷100

=(90×110)÷100

=99

SP of 11 oranges = SP of 24 oranges

therefore,SP of 11 oranges = 99

SP of 1 orange = 99÷11

=9

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