A fruit seller buys a stock of 200 oranges at 6:00 each and another stock of 200 orange at rupees 8 each while sorting through them if there are 40 root and orange which he cannot self find the price at which he must sell each orange so as to make a profit of 10% in the complete transaction how to solve it
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must sell each orange at Rs 8.55 to get 10% profit on overall transaction if 200 bought at 6 , 200 bought at 8 and 40 were unsellable.
Step-by-step explanation:
buys a stock of 200 oranges at 6 each
=> Cost Price = 200 * 6 = Rs 1200
buys a stock of 200 oranges at 8 each
=> Cost Price = 200 * 8 = Rs 1600
Total Cost Price = 1200 + 1600 = Rs 2800
Total Oranges = 200 + 200 = 400
Rotten = 40
Sellable Orange = 400 - 40 = 360 Oranges
Selling Price of Each Orange = P
Total Selling Price = 360P
360P = 2800 + (10/100)2800
=> 360P = 3080
=> P = 77/9 = 8.55 Rs
must sell each orange at Rs 8.55
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