Math, asked by XxAvIxX11, 29 days ago

A fruit seller buys some apples at rupees 5 per Apple he also buys an equal number of Bananas at rupees 2 per banana he makes a 20% profit on apples and 15% profit on Bananas at the end of the day De all fruits are sold out is total profit is rupees 390 find the number of Apple he purchased​

Answers

Answered by rishipranaav1
4

Answer:

Given :-

A fruit seller buys some apples at rupees 5 per Apple he also buys an equal number of Bananas at rupees 2 per banana he makes a 20% profit on apples and 15% profit on Bananas at the end of the day De all fruits are sold out is total profit is rupees 390

To Find :-

Number of apples

Solution :-

Let the CP of apple and banana be a

CP of apple = 5 × a = 5a

CP of banana = 2 × a = 2a

Now

ATQ

We know that

SP = (100 + Profit %)/100 × CP

SP = (100 + 20)/100 × 5a

SP = 120/100 × 5a

SP = 24/20 × 5a

SP = 24/4 × a

SP = 24a/4

SP = 6a

Now

On bananas

SP = (100 + Profit%)/100 × CP

SP = (100 + 15)/100 × 2a

SP = 115/100 × 2a

SP = 23/20 × 2a

SP = 23a/10

Now

Total SP = 5a + 2a

Total SP = 7a

Total CP = 6a + 23a/10

Total CP = 60a + 23a/10

Total CP = 83a/10

Now

Profit = SP - CP

Profit = 83a/10 - 7a

390 = 83a - 70a/10

390 × 10 = 83a - 70a

3900 = 13a

3900/13 = a

300 = a

Answered by karnkamal990
79

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