Question

a fruit seller had some apples he sells 40% apples and still has 420 apples how many apples did he originally have
$with correct solutin$
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Answer 1

Step-by-step explanation:

let the total apples be x

x- 30x/100 =420

x-3x/10=420

Taking LCM

(10x-3x)/10=42

7x=4200

x=600

He originally had 600 apples

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Answer 2

Given :

A fruit seller had some apples. He sells 4O% apples and still has 320 apples.

To find :

How many apples did he originally have?

Using formula :

★ Number of originally the fruit seller have = Number of apples left/Percentage of apples didn't sell × 100.

Calculations :

We know that, in a sum of overall 100% of apples he sells 40% of apples so we have to find the number of percentage he didn't sold.

→ 100% - 40%

→ 60% [He didn't sell]

Solution :

→ 420/60 × 100

→ 7 × 100

→ 700 apples

Therefore, the number of apples he original have is 700 apples.