A fruit seller had some apples. He sells 40% apples and still has 420 apples . orginally ,he had
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Let the original he had to be x.
Given that he sells 40% apples.
= > 100 - 40
= > 60%.
Given that he still has 420 apples.
= > 60% of x = 420
= > (60x)/100 = 420
= > 60x = 420 * 100
= > 60x = 42000
= > x = 700.
Therefore he originally had 700 apples.
Hope this helps!
Given that he sells 40% apples.
= > 100 - 40
= > 60%.
Given that he still has 420 apples.
= > 60% of x = 420
= > (60x)/100 = 420
= > 60x = 420 * 100
= > 60x = 42000
= > x = 700.
Therefore he originally had 700 apples.
Hope this helps!
siddhartharao77:
:-)
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Given :
A fruit seller had some apples. He sells 4O% apples and still has 320 apples.
To find :
How many apples did he originally have?
Using formula :
★ Number of originally the fruit seller have = Number of apples left/Percentage of apples didn't sell × 100.
Calculations :
We know that, in a sum of overall 100% of apples he sells 40% of apples so we have to find the number of percentage he didn't sold.
→ 100% - 40%
→ 60% [He didn't sell]
Solution :
→ 420/60 × 100
→ 7 × 100
→ 700 apples
Therefore, the number of apples he original have is 700 apples.
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