A fruit seller has 30 kg of fruit. If 42/5 kg of these fruits are Apples, 23/4 kg are oranges, 23/3 kg are bananas and rest are papayas, find the weight of papayas.
Answers
Answer:
hello mate
total 30kg
i.e. 42/5 +23/4 +23/3+x=30
therefore
lcm=The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Since
3
has no factors besides
1
and
3
.
3
is a prime number
4
has factors of
2
and
2
.
2
⋅
2
Since
5
has no factors besides
1
and
5
.
5
is a prime number
The LCM of
3
,
4
,
5
is the result of multiplying all prime factors the greatest number of times they occur in either number.
2
⋅
2
⋅
3
⋅
5
The LCM of
3
,
4
,
5
is
2
⋅
2
⋅
3
⋅
5
=
60
.
therefore 42*12/60 + 23*15/60 + 23*20/60 +x
= 504+345+460+x/60
1309+x/60=30
30kg=30*60/60
lcm
30kg = 1800/60
therefore x= 1800-1309/60
papyas= 491/60 kgs
Explanation:
plz mark me as the brainliest hope it helps need 2 more to power up