Question

A fruit seller has certain number of apples of which 5% are rotten.He sells 93% of the remainder and then has 266 left.Hiw many apples he had originally

Answer 1

Let, the total number of apple be, 'x'

5% of x =5x/100

              = x/20

No. of apples left =(x-x/20)

                            =(20x-x)/20

                            = 19x/20

93% of 19x/20 =(19x/20)*(93/100)

                      =(19x*93)/(20*100)

                     =1767x/2000

No, of apples left =(19x/20)-(1767x/2000)

                             = (1900x-1767x)/2000

                           =233x/2000

By condition,

233x/2000=266

or, x = 266*2000/233

or, x = 2283 apples approx.

So, he had 2283 apples

Answer 2

Step-by-step explanation:

Let, the total number of apple be, 'x'

5% of x =5x/100

              = x/20

No. of apples left =(x-x/20)

                            =(20x-x)/20

                            = 19x/20

93% of 19x/20 =(19x/20)*(93/100)

                      =(19x*93)/(20*100)

                     =1767x/2000

No, of apples left =(19x/20)-(1767x/2000)

                             = (1900x-1767x)/2000

                           =233x/2000

By condition,

233x/2000=266

or, x = 266*2000/233

or, x = 2283 apples approx.

So, he had 2283 apples