Question

A fruit seller have three types of fruit in his bucket namely Mango, Orange and Papaya. The probability of
selling one mango is 2/7 and one orange is 1/6. If seller have total 46 papaya in his bucket then find total
number of fruits in seller bucket?
1.78
2. 84
3.96
4. 80
5. 72
​

Answer 1

Answer:

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Answer 2

Answer:

Whenever it is not explicity mentioned that fruit and distint, We take them as identical. 0 or more orange can be selected from 4 identical oranges in (4+1)=5 ways. 0 or more apples can be selected from 5 identical apples in (5+1)=6 ways.

0 or more mangoes can be selected from 6 identical mangoes in 7 ways.

∴ Total no. of ways in which all of three types of fruits can be selected (the no. of any type of fruits may also be 0),

5×6×7=210,

But in these 20 selection, there is one selection where all fruits are 0, hence we reduce 1 selection.

∴ the required no. =210−1=209

Please refer this as it is the same method and you can write your answer by yourself.