Math, asked by sumantakumar0338, 18 days ago

A fruit seller purchased 20 kg of apples at Rs 300. Out of total quantity, 2 kg of apples were rotten. At what price per kg he should sell the balance quantity of apples to get a profit of 20%? (B) Rs. 20 (A) Rs. 36 (6) Rs. 18 (D) Rs. 15 ​

Answers

Answered by kavyansh25
0

Answer:

D). 15

first we find 1 kg then multiply it with 1 kg because 2 kg is rotten..

Answered by prasanshadwivedi321
1

Answer:

the cost price of 20 kg of apples= Rs.300

quantity of apples which are rotten=2 kg

remaining good apples=20-2= 18kg

So,

the cost of 18 kg of apples= Rs. 300

desired profit=20%

Selling price= [(100+g)/100]×CP

SP=[(100+20)/100]×300

SP= (120/100)×300

SP= ( 120×300)/100

SP=120×3

SP=Rs. 360

So, the selling price of 18 kg apples=Rs. 360

the cost of 1kg of Apple= 360/18

Rs. 20

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