Question

A fruit seller purchased 20 kg of apples at Rs300. Out of total quantity , 2 kg of apples were rotten .
At what price per kg he should sell the balance quantity of apples to get a profit of 20%

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Answer 1

Explanation:

Given :-

A fruit seller purchased 20 kg of apples at Rs300. Out of total quantity , 2 kg of apples were rotten .

To find :-

At what price per kg he should sell the balance quantity of apples to get a profit of 20% ?

Solution :-

Given that

The Cost Price of 20kg of apples

= Rs. 300

Quantity of apples which are rotten

= 2 kg

Remaining good apples = 20-2 = 18 kg

So,

The Cost of 18 kg of apples = Rs. 300

Desired profit = 20%

We know that

Selling Price = [(100+g)/100]×CP

=> SP = [(100+20)/100]×300

=> SP = (120/100)×300

=> SP = (120×300)/100

=> SP = 120×3

=> SP = Rs. 360

So, The Selling Price of 18 kg of apples

= Rs. 360

The Cost of 1 kg of apples

= 360/18

=> Rs. 20

Answer :-

The fruit seller should sell 1 kg of apples at Rs. 20 to get the desired profit.

Used formulae:-

→Selling Price = [(100+g)/100]×CP

Answer 2

$\bold{ANSWER≈}$

Given :

A fruit seller purchased 20 kg of apples at Rs300. Out of total quantity, 2 kg of apples were rotten.

To find :

At what price per kg he should sell the balance quantity of apples to get a profit

of 20% ?

Solution :

Given that

The Cost Price of 20kg of apples

= Rs. 300

Quantity of apples which are rotten

= 2 kg

Remaining good apples = 20-2 = 18 kg

So,

The Cost of 18 kg of apples = Rs. 300 Desired profit = 20%

We know that

Selling Price = [(100+g)/100]*CP

=> SP = [(100+20)/100]x300

=> SP (120/100)x300

=> SP = (120×300)/100

=> SP = 120x3

=> SP = Rs. 360

So, The Selling Price of 18 kg of apples

= Rs. 360

The Cost of 1 kg of apples

= 360/18

=> Rs. 20

Answer :

The fruit seller should sell 1 kg of apples at Rs. 20 to get the desired profit.

Used formulae:

→Selling Price = [(100+g)/100]*CP