Math, asked by omthelegend, 1 year ago

a fruit seller purchased 48 dozens oranges at the rate of ₹48 per dozen, out of that 1 dozen oranges were spoiled.He sold the remaining oranges at the rate of ₹6 per orange.Find the profit that he earned in this transaction.

Answers

Answered by kushanaanandp4ac8a
46
Oranges purchased=48 dozen.
Price per dozen= 48 Rs.
Total cost price= 48*48= 2304Rs.
Oranges spoiled=1 dozen.
Oranges remaining=48-1=47 dozen
Total number of oranges= 47*12=564 oranges.
Selling price per orange=6.
Total selling price=564*6=3384.

Therefore, profit= selling price- cost price.
=3384-2304.
=1080Rs.

Hope this helps.
Answered by apriyanshu885
12

Answer:


Step-by-step explanation:

Oranges purchased=48 dozen.

Price per dozen= 48 Rs.

Total cost price= 48*48= 2304Rs.

Oranges spoiled=1 dozen.

Oranges remaining=48-1=47 dozen

Total number of oranges= 47*12=564 oranges.

Selling price per orange=6.

Total selling price=564*6=3384.


Therefore, profit= selling price- cost price.

=3384-2304.

=1080Rs.


Hope this helps.




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