Question

A fruit seller sells 25 kg of apples at a profit of 8%. If the CP of 1 kg apple is 35, find the SP of 1 kg​

Answer 1

Given :

• Selling Price of 25 kg apples = 8 % Profit
• Cost Price of 1 kg apple = Rs. 35

To find :

• Selling Price of 1 kg of apples

Solution :

We know that,

Cost Price of 1 kg apples = $\sf{Rs.\:35}$

Cost Price of 25 kgs of apples would be = $\sf{25\:\times\:35}$ = $\sf{Rs.\:875}$

So, The cost price of 25 kgs of apples are = Rs. 875.

Selling Price,

$\boxed{SP\:=\:{\dfrac{100\:+\:Profit\:Percent}{100}}\:×\:CP}$

Substituting values in Formula, we get,

$\implies\sf{SP\:=\:{\dfrac{100\:+\:8}{100}}\:×\:CP}$

$\implies\sf{SP\:=\:{\dfrac{108}{100}}\:×\:CP}$

$\implies\sf{SP\:=\:{\cancel{{\dfrac{108}{100}}\:×\:CP}}}$

$\implies\sf{SP\:=\:Rs.\:170}$

Hence, The selling price of 1 kg of apples are = Rs. 170.

Answer 2

Answer:

Step-by-step explanation:

Explanation

Profit %=8%

C.P of 1 kg apples=Rs 35

So,

S.P is given by S.P = (1+100profit​)∗C.P

S.P=(1+1008​)∗35

S.P = 100108​∗35

S.P = Rs 37.8 (Answer)