Math, asked by sringerinaik, 26 days ago

a fruit seller sold 48 kgs of mango in the morning and 57 kgs of mangos in the evening. it the mangoes cost ₹80 per kg, how much did the fruit seller collect on that day?​

Answers

Answered by GraceS
2

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Given :

Mangoes sold in morning = 48 Kgs

Mangoes sold in evening = 57 Kgs

Cost of mangoes per Kg = ₹80

To find :

Total amount the fruit seller collect on that respective day.

Solution :

⇒ Total number of mangoes sold in a day

= mangoes sold in morning + mangoes sold in evening

= 48 Kgs + 57 Kgs

= 105 Kgs

⇒ Cost of mangoes per Kg = ₹80

⇒Total Cost of mangoes sold in a day

= Cost of 105 Kgs of mangoes

= ₹80 × 105

= ₹8400

Hence, the fruit seller collect 8400 on that respective day.

Answered by pavankumar7712
1

Answer:

8400

Step-by-step explanation:

total mangoes he sold was 105 kg

cost of mango is per kg is 80

so he earn is 80×105=8400

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