Question

A fruit seller was selling imported bananas. I told him to give me Rs. 120 worth of bananas. After he gave me the bananas, I told him that they were too small, and forced him to give me 2 extra bananas for free. He complained that because of giving me these two extra bananas, he is getting Rs. 10 per dozen less on this transaction than the original price. How many bananas did I get (including the 2 extra bananas)?

Answer 1

Answer:

16 + 2 = 18 bananas

Explanation:

Let p be the price per banana, and n be the number of bananas I got.

So, p x n = 120, as given.

However, I received (n+2) bananas, at the same price of 120, which earned the seller Rs 10 less per dozen. So, the price that he should have received is 120 + 10/12 x (n+2).

So we can write our 2nd equation as p x (n+2) = 120 + 10/12 x (n+2)

Solving the quadratic equation, we get n=16 as the only whole number root.

So the ans including the 2 extra bananas is 16+2 = 18 bananas.

Answer 2

Answer:

Bananas she got (including the 2 extra bananas)= 18 bananas

Explanation:

In the above question;

Given:

Total bananas she wants depends on the money she gave which is Rs. 120

Fruit seller gave small bananas- to compensate she asked for 2 extra

Fruit seller gets Rs. 10 per dozen after giving extra bananas.

To find:

How many bananas she got?

Solution:

Total price payed by her= Rs 120

Let m be the bananas she got and n be the price for each banana.

Then, m×n= 120(as given in the question) or we can also write m=120÷n

Now, the question says she wants 2 extra bananas, the number of bananas will then become- m+2

Loss of fruit seller= Rs 10 per dozen which means Rs 10/12

Price then becomes= n-10/12

The new equation will then become:

Before- m×n= 120

Now- (m+2)×(n-10/12)= 120

Solving the equation:

(m+2)×(12n-10/12)=120

(m+2)×(12n-10)=120×12

We can also write the m as m=120÷n( as mentioned earlier)

Therefore,

(120/n+2)×(12n-10)= 1440

(120+2n)×(12n-10)= 1440

1440n-1200+24n²-20n=1440n

1440n cancels out;

We are left with -1200+24n-20n=0 or,

24n²-20n-1200=0

taking common factor: 4(6n²-5n-300)=0

 Now using sum product pattern we get:

4(6n²+40n-45n-300)=0

Solving this we get:

n=7.5(price per banana)

we want to find out x:

As we have seen, x= 120/n

                               x=120/7.5

                                x= 16

Including the 2 extra bananas: x will be equal to 16+2= 18 bananas

#SPJ2