Question

a fruit sellers has some fruit with him he threw any 10% of the fruits because they were spoiled he sold 50% of the remaining fruits and then had 90 fruits with him how many fruits he had in a beginning​

Answer 1

Step-by-step explanation:

Let total no. Of mangoes = x

Spoiled mangoes were= 10 %

Then, left mangoes = x - 10% of x

Means, 9/10 x

Sold mangoes were = 75%

Then, left mangoes = (100-75)%

ATQ:

25% of x = 90

25/100* 9/10 x = 90

9/40 x = 90

X = (90 * 40)/9

X = 400

Therefore, total mangoes = 400

Answer 2

Answer:

200 fruits

Step-by-step explanation:

As we know that fruit seller threw 10% spoiled

So remaining fruits = 100-10 = 90%

=> now he sold 50 % of remaining

means => 50/100×90 = 45 %

now remaining fruits %age is = 100-(45+10) = 45%

and in quantity = 90

if 45% = 90 fruits

then 100 % = ?

=> 100/45 ×90 = 200 fruits