Math, asked by vandiadevan, 1 year ago

A fruit vendor bought some mangoes of which 10% were rotten. He sold
33 1/3% of the rest. Find the total number of mangoes bought by him initially,
if he still has 240 mangoes with him.

Answers

Answered by lipimohapatra01
57

Let the no. of mangoes bought by a fruit vendor=100

The no. of rotten mangoes =10%of bought mangoes=

10%of 100=10/100×100=10mangoes

The rest mangoes=100-10=90 mangoes

He sold (33 1/3)% of the rest

=(33 1/3)%of 90

=(100/3)/100×90

= 100/3×1/100×90

=90/3=30 mangoes

As per the above assumption,he still have the mangoes=100-(30+10)

(30 is the no.sold mangoes and 10 is the no.of rotten mangoes)

=100-40=60 mangoes

As per the question,

He still have 240 mangoes

When the rest mangoes= 60, the no. of bought mangoes=100

When ,, =1, ,,

bought mangoes=100/60

When the rest mangoes=240,the no. of

bought mangoes=100/60×240

=400 mangoes

Hence ,the total no. of mangoes bought by him=400 mangoes. (ANS)

Answered by 8703anushya2122
0

Answer:

Let the number of mangoes bought by fruit seller initially be x.

Given that 10% or mangoes were rotten

∴ Number of rotten mangoes = 10100 × x

Number of good mangoes = x – no. of rotten mangoes

= x−10100x=100x−10x100=90100x …….. (1)

Number of mangoes sold = 3313% of good mangoes = 1003%

∴ Mangoes sold = 1003×90100××1100=30100x ……. (2)

Number of mangoes remaining = No. of good mangoes – No. of mangoes sold

∴ Intially he had 400 mangoes

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