Question

A fruit vendor buys orange at 6 for ₹ 10 and an equal number at 10 for ₹ 20 he mixex them and sells at ₹ 2160 per dozen find his gain or loss per cent​

Answer 1

Step-by-step explanation:

Answer: There is a loss percentage of 1.81%.

Step-by-step explanation:

Since we have given that

A fruit vendor has to purchase equal number of oranges .

And we have selling price of per dozen = Rs. 21.60

So, it means ,

He purchased 6 oranges each from two cases.

From First case:

Cost of 6 orange = Rs. 10

From Second case:

Cost of 10 oranges = Rs. 20

Cost of 6 oranges is given by

\begin{gathered}\frac{20}{10}\times 6\\\\=Rs.12\end{gathered}

10

20

×6

=Rs.12

So, Total cost of 1 dozen becomes

10+12=Rs.2210+12=Rs.22

Now, We can see that

Cost price > Selling price

So, there is a loss.

We need to find the loss percentage.

\begin{gathered}Loss=Cost-Selling\\\\loss=22-21.60\\\\Loss=0.40\end{gathered}

Loss=Cost−Selling

loss=22−21.60

Loss=0.40

and Loss % is given by

\begin{gathered}Loss\%=\frac{Loss}{Cost}\times 100\\\\Loss\%=\frac{0.40}{22}\times 100\\\\Loss\%=1.81\%\end{gathered}

Loss%=

Cost

Loss

×100

Loss%=

22

0.40

×100

Loss%=1.81%

Hence, there is a loss percentage of 1.81%.

Answer 2

Step-by-step explanation:

Let the no. of oranges =x= no. of bananas 

cost price =5x+2x=7x

Gain on oranges =10020×5x=x

Gain on Bananas =10015×2x=0.3x

Profit ⇒1.3x=390

⇒x=1.3390=300

No. of oranges purchased =300