Question

A fruit vendor buys oranges at 6 for 10 and an equal number at 10 for 20. He mixes them and sells at 21.60 per dozen. Find his gain or loss per cent.​

Answer 1

Answer:

Now, here we have been given that the cost price of six type 1 oranges is Rs. 10 and that of 10 type two oranges is Rs. 20. The selling price of the mixture of the two types of oranges is Rs. 21.60 per dozen. So we consider that 6 oranges of both types are present in the mixture. Let us find the total C.P of 6 oranges of both types.

(1) For type 1 orange it is already given that the cost price of 6 oranges is Rs. 10.

(2) For type 2 oranges it is given that the cost price of 10 oranges is Rs. 20. So applying the unitary method we have,

⇒ Cost price of 6 oranges of type 2 = Rs. 2010×6

⇒ Cost price of 6 oranges of type 2 = Rs. 12

Therefore, if we mix 6 oranges of both types to find the total cost price of a mixture of dozen oranges we get,

⇒ Total cost price of mixture of oranges = Rs. (10 + 12) = Rs. 22

Clearly we can see that the Cost price of the mixture is more that the Selling price of the mixture so the fruit vendor will suffer loss given as loss % = C.P−S.PC.P×100%

, where C.P = Cost Price and S.P = Selling Price. Therefore we get,

⇒ Loss % = 22−21.6022×100%

∴ Loss % = 1.818 %

Answer 2

Answer:

Loss4%

Step-by-step explanation:

C.P of 6 oranges = Rs 10

C.P of 10 oranges = Rs 20

Total C.P of 16 oranges = Rs 30

C.P of 1 orange = 30/16 = 1.875

S.P of 12 orange = 21.6

S.P of 1 orange = 21.6/12 = 1.8

Loss = C.P - S.P = 1.875-1.8 = 0.075

Loss% = 0.075*100/1.875 = 4%