A fruit vendor buys some oranges at the rate of 5 per orange. He also buys an equal
number of bananas at the rate of 2 per banana. He makes a profit of 20% on oranges and
15% on bananas. At the end of the day, all the fruits are sold out. His total profit is * 390.
Find the number of oranges purchased.
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Ur answer is here ⤵
Ans will be 300 oranges
solution:
let
the no of orange bought by the vendor be X
according to question:
no of orange bought by the vendor = no of banana bought by the vendor = X
now;
cost of orange at which vendor bought =₹5
then cost of X no of orange will be = ₹5X
cost of banana at which the vendor bought = ₹2
then cost of X no of banana will be = ₹2X
also, according to the question:
vendor sells the orange at a profit of 20% i.e, he sells it at the price of =
5X ×20/100 +5X= ₹6X
also vendor sells the banana at a profit of 15% i.e,he sells it at the price of=
2X×15/100 +2X= ₹ 23X/10
according to the question his total profit is ₹390 i.e,
(final price of orange- initial price of orange) +(final price of banana - initial price of banana) =₹390
(6X-5X) + (23X/10-2X) = 390
X +3X/10 =390
13X/10 = 390
X =390 ×10/13
X=300
Hope it's help you ✌
Ur answer is here ⤵
Ans will be 300 oranges
solution:
let
the no of orange bought by the vendor be X
according to question:
no of orange bought by the vendor = no of banana bought by the vendor = X
now;
cost of orange at which vendor bought =₹5
then cost of X no of orange will be = ₹5X
cost of banana at which the vendor bought = ₹2
then cost of X no of banana will be = ₹2X
also, according to the question:
vendor sells the orange at a profit of 20% i.e, he sells it at the price of =
5X ×20/100 +5X= ₹6X
also vendor sells the banana at a profit of 15% i.e,he sells it at the price of=
2X×15/100 +2X= ₹ 23X/10
according to the question his total profit is ₹390 i.e,
(final price of orange- initial price of orange) +(final price of banana - initial price of banana) =₹390
(6X-5X) + (23X/10-2X) = 390
X +3X/10 =390
13X/10 = 390
X =390 ×10/13
X=300
Hope it's help you ✌
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