Question

A fruit vendor has 318 apples , 848 bananas and 689 oranges. These fruits have to be put in heaps of equal numbers . what us the maximum number of fruits in a heap

Answer 1

Answer:

Maximum number of fruits in a heap are 53.

Explanation:

A fruit vendor has 318 apples, 848 bananas and 689 oranges. These fruits have to put in heaps of equal numbers.

We need to calculate the maximum number of fruits in a heap.

Maximum number of fruits in a heap is HCF of all three number.

First we find the HCF of all three number.

Prime factorization of each number:

$318=2\times 3\times 53$

$848=2\times 2\times2 \times2 \times 53$

$689=13\times 53$

As we can see 53 is only number which is common in all three factors.

$\therefore \text{HCF }=53$

Thus, Maximum number of fruits in a heap are 53.

Answer 2

ANSWER -

Maximum number of fruits in a heap are 53.

EXPLANATION -

A fruit vendor has 318 apples, 848 bananas and 689 oranges. These fruits have to put in heaps of equal numbers.

We need to calculate the maximum number of fruits in a heap.

Maximum number of fruits in a heap is HCF of all three number.

First we find the HCF of all three number.

Prime factorization of each number:

318 = 2 × 3 × 53

848 = 2 × 2 × 2 × 2 × 53

689 = 13 × 53

As We can see 53 is only number which is common in all three factors.

∴ HCF = 53

Thus, Maximum number of fruits in a heap are 53.