Question

A fruit vendor has 990 apples and 945 oranges.he packs them into baskets.each basket contains only one of the two fruits but equal in number.find the no. Of fruits to be put in each basket in order to have minimum no. Of baskets .answer with reasons plsss

Answer 1

Answer:

45

Step-by-step explanation:

Given :

A fruit vendor has 990 apples and 945 oranges.

He packs them into baskets.

Each basket contains only one of the two fruits but equal in number.

To Find :the no. Of fruits to be put in each basket in order to have minimum no. Of baskets

Solution :

To find the no. of required baskets such that Each basket contains only one of the two fruits but equal in number.

We will find the H.C.F i.e. highest common factor

H.C.F : The largest common factor of two or more numbers is called the highest common factor

Thus 990= 2*3*3*4*5

945 = 3*3*3*5*7

Thus HCF = 3*3*5 =45 (REFER THE ATTACHED FIGURE )

Thus the no. of fruits to be put in each basket in order to have minimum no. of baskets  = 45

Answer 2

Answer:

45

Step-by-step explanation:

990 = 945 x 1 + 45

945 = 45 x 21 + 0

so 45 is correct answer